Mathematics

Eleven Standard

Test your understanding of this lesson Product formula of compound angles:-

1)
\(90^{0}<\theta<180^{0}\) and \(\sin\theta=\frac{3}{5}\), \(\tan\phi=\frac{5}{2}\), then \(\sin(\theta+\phi)\) is
  • \(\frac{7}{65}\)
  • \(\frac{16}{65}\)
  • \(\frac{5}{13}\)
  • \(\frac{24}{65}\)
2)
If A+B=\(225^{0}\) then \(\frac{\cot B-\cot A}{1+\cot A\cot B}\) is
  • 1
  • -1
  • -\(\frac{1}{2}\)
  • \(\frac{1}{2}\)
3)
If \(\sin^{2}(\frac{\pi}{8}+\frac{\theta}{2})-\sin^{2}(\frac{\pi}{8}-\frac{\theta}{2})=k\sin\theta\), then k is
  • -\(\frac{1}{\sqrt{2}}\)
  • \(\frac{1}{\sqrt{2}}\)
  • \(\frac{1}{2}\)
  • -\(\frac{1}{2}\)
4)
The value of \(\tan75^{0}-\cot75^{0}\) is
  • 4
  • \(2+\sqrt{3}\)
  • \(2-\sqrt{3}\)
  • \(2\sqrt{3}\)
5)
Value of \(\tan20^{0}+\tan40^{0}+\sqrt{3}\tan20^{0}\tan40^{0}\) is
  • \(\frac{\sqrt{3}}{2}\)
  • \(\frac{\sqrt{3}}{4}\)
  • \(\sqrt{3}\)
  • -\(\frac{\sqrt{3}}{2}\)

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