Question: In a group of 60 people, 37 like tea, 35 like coffee, and each person likes at least one of the two drinks. Find the number of persons who like: i) both tea and coffee ii) only tea iii) only coffee iv) neither tea nor coffee v) exactly one of the drinks.
Let:
We use the formula:
n(T ∪ C) = n(T) + n(C) − n(T ∩ C)
Substitute the known values:
60 = 37 + 35 − n(T ∩ C)
n(T ∩ C) = 72 − 60 = 12
Answer: 12
n(Only Tea) = n(T) − n(T ∩ C) = 37 − 12 = 25
n(Only Coffee) = n(C) − n(T ∩ C) = 35 − 12 = 23
Since everyone likes at least one, the answer is 0
n(Exactly one) = n(Only Tea) + n(Only Coffee) = 25 + 23 = 48